ABCD is a square of perimeter 56m. Two triangular corners have been cut away as shown in figure. What is the perimeter of the remaining figure?
A
39m
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B
42m
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C
35m
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D
53m
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Solution
The correct option is B42m Perimeter of square=56m ⇒4× side of square =56m ⇒ Side of square =(56+4)=14m Now, AE+ED=14m ⇒7m+ED=14⇒ED=7m and ED=CG=7m ∴ Perimeter of remaining figure =ED+DC+CG+GF+FE =(7+14+7+7+7)m=42m.