Question

# ABCD is a square with side a. With centres A,B,C and D four circles are drawn such that each circle touches externally two of the remaining three circles. Let δ be the area of the region in the interior of the square and exterior of the circles. Then the maximum value δ is:

A
a2(1π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a2(4π4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a2(π1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
πa24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B a2(4−π4)Area of Interior region = Area of square − Total area of circles inside the squareArea of square = side2 = a2Area of portion of 4 circles = 4×(14πr2) =4×(14π(a2)2) = πa24Thus, area of Interior region = a2−πa24= a2(4−π4)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Perimeter
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program