Question

# ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). From the figure, which of the following can be deduced? None of these ΔABC≅ΔBCD ΔABC≅ΔBCE ΔABC≅ΔBAD

Solution

## The correct option is D ΔABC≅ΔBAD In ΔABC and  ΔABD, AB = BA  (Common side) BC = AD  (Given) ∠B=∠A (Proved before) ΔABC≅ΔBAD (SAS congruence rule)

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