MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

The Mid-Point Theorem

ABCD is a tra...

Question

ABCD is a trapezium in which AB || DC and let E be the midpoint of AD. Let F be a point on BC such that EF || AB. Then MF is

A

1/2 DC

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1/3 AB

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1/4 DC

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

1/2 AB

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1/2 DC

Suggest Corrections

thumbs-up

3

Similar questions

Q. ABCD is a trapezium in which side AB is parallel to DC and E is the mid point of side AD. If F is a point on BC such that the line segment EF is parallel to DC, then prove that EF = 1/2(AB+DC)

Q. In the figure,

□ A B C D

is a trapezium,

A B ∥ D C

P

Q

are midpoints of

s e g A D

s e g B C

respectively. Then prove that,

P Q ∥ A B

P Q = \frac{1}{2} (A B + D C)

.

Q. In a trapezium ABCD, AB|| DC and DC = 2AB, FE drawn parallel to AB cuts AD in F and BC in E such that 4BE = 3EC. Diagonal DB intersects EF at G. Prove that 7FE = 10 AB. [4 MARKS]

Q. In a trapezium ABCD,

A B ∥ D C

D C = 2 A B

. EFdrawn parallel to AB cuts AD in F and BC in E such that

\frac{B E}{E C} = \frac{3}{4}

. Diagonal DB intersects

E F

G

Q. In a trapezium

A B C D, A B ∥ D C

D C = 2 A B

E F

drawn parallel to

A B

A D

F

B C

E

\frac{B E}{E C} = \frac{3}{4}

D B

E F

G

7 F E = 10 A B

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

The Mid-Point Theorem

MATHEMATICS

Watch in App

explore_more_icon

Explore more

The Mid-Point Theorem

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon