CameraIcon

SearchIcon

MyQuestionIcon

4

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Area of Trapezium by Division into Shapes of Known Area

ABCD is a tra...

Question

$A B C D$ is a trapezium in which $A B ∥ D C$ , AB=29cm, DC=20cm, and height=15cm.Find the area of trapezium.

Open in App

Solution

Area of trapezium $= \frac{1}{2}$ (Sum of parallel sides) $\times$ height
$= \frac{1}{2} \times (29 + 20) \times 15$
$= \frac{1}{2} \times 49 \times 15$
$= 367.5 c m^{2}$

Suggest Corrections

thumbs-up

0

Similar questions

A B C D

is trapezium in which

A B ∥ D C, A B = 78 c m, C D = 52 c m, A D = 28 c m

B C = 30 c m

. Find the area of the trapezium.

Q. In the given figure, ABCD is a trapezium in which AB = 7 cm, AD = BC = 5 cm, DC = x cm, and distance between AB and DC is 4 cm. Find the value of x and area of trapezium ABCD.

Q. In trapezium

A B C D

A B ∥ D C, A D = D C = B C = 20 c m

A = 60^{\circ}

. Find:
Distance between

A B

D C

.

Q. In trapezium

A B C D

A B / / D C

A D = D C = B C = 20 c m

∠ A = 60^{\circ}

. Distance between

A B

D C

Q. ABCD is a trapezium in which

A B ∥ C D,

if AB=7 cm, DC=3 cm and if the area of the trapezium is 18

c m^{2}

, then the area of

△ B C D

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trapezium

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Area of Trapezium by Division into Shapes of Known Area

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon