Question

$ABCD$ is a trapezium in which $AB\parallel DC$, $M$ and $N$ are the midpoints of $AD$ and $BC$ respectively. If $AB=12cm;MN=14cm$ find $CD$.

• A. $8cm$
• B. $16cm$
• C. $6cm$
• D. $36cm$

Answer 1

The correct option is B $16cm$

Given AB=12cm , MN=14cm

Since ,segment joining the mid-point of non-parallel sides of trapezium is half the sum of the lengths of its parallel sides.

$\Rightarrow MN=\frac{1}{2}(AB+DC)$

$14=\frac{1}{2}(12+CD)$

$CD=28-12$

$CD=16cm$