Question

ABCD is a trapezium with AB $\parallel$ CD. A line parallel to DB intersects CD at X and BC at Y. If area($△$BDY) = 5 $c{m}^2$,
then ar($△$ADX) is

• A. 2.5 cm²
• B. 5 cm²
• C. 7.5 cm²
• D. 10 cm²

Answer 1

Answer: (B)

5 cm²

Triangles DYB and DXB are on same base BD and between same parallels BD and XY.

So, Area of triangle DXB = 5 $c{m}^2$

Again triangles DXB and ADX are on same base DX and between same parallels CD and AB.

So, Area of triangle ADX = 5 $c{m}^2$