Question

ABCD is an isosceles trapezium . AB and DC are the parallel sides. Perpendicular DE and CF are drawn on AB. Find out if $△ADE\cong △BCF$ ?

Answer 1

Solution:

In $△ADE$ and $△BCF$

$\angle A=\angle B$ (Base angle is same in Isosceles)

$\angle CFB=\angle DEA={90}^{\circ }$

$AD=BC$

$△ADE\equiv △BCF$ (by ASA)