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Standard IX

Mathematics

Angle Sum Property of a Quadrilateral

ABCD is equil...

Question

ABCD is equilateral $△ B E C$ is rectangle to BD cross ED at 'O' point $∠ B O C =$ ?

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Solution

$△ B E C$ is equilateral
So $∠ B C O = 60^{\circ}$
In square, the diagonals make $45^{\circ}$ with sides of square.
In $△ B O C$
The sum of angles is $180$
$∠ B + ∠ C + ∠ O = 180 45 + 60 + ∠ O = 180 ∠ B O C = 180 - 105 = 75^{\circ}$

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ABCD is equilateral △BEC is rectangle to BD cross ED at 'O' point ∠BOC=?

△BEC is equilateralSo ∠BCO=60∘In square, the diagonals make 45∘ with sides of square.In △BOCThe sum of angles is 180∠B+∠C+∠O=18045+60+∠O=180∠BOC=180−105=75∘'

ABCD is equilateral $△ B E C$ is rectangle to BD cross ED at 'O' point $∠ B O C =$ ?

$△ B E C$ is equilateral
So $∠ B C O = 60^{\circ}$
In square, the diagonals make $45^{\circ}$ with sides of square.
In $△ B O C$
The sum of angles is $180$
$∠ B + ∠ C + ∠ O = 180 45 + 60 + ∠ O = 180 ∠ B O C = 180 - 105 = 75^{\circ}$

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