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Question

ABCD is parallelogram. If AB=a,BC=b then show that AB=a,+b and BD=b,a ?

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Solution

Given ABCD is a parallalogaram and

¯¯¯¯¯¯¯¯AB=¯¯¯a,¯¯¯¯¯¯¯¯BC=¯¯bHere,¯¯¯¯¯¯¯¯ACistheresultof¯¯¯¯¯¯¯¯AEand¯¯¯¯¯¯¯¯ECso¯¯¯¯¯¯¯¯AC=¯¯¯¯¯¯¯¯AE+¯¯¯¯¯¯¯¯EC=(a+bcosθ)2+(bsinθ)2a2+b2cos2θ+2abcosθ+b2sin2θa2+b2+2abcosθ|a+b|¯¯¯¯¯¯¯¯AB=¯¯¯a+¯¯bsimilerily¯¯¯¯¯¯¯¯¯BD=¯¯b¯¯¯a

1129915_1109675_ans_77d4bbe92fa649ae9b515f0a3368e7e9.JPG

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