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Standard VIII

Mathematics

Area of a General Quadrilateral

ABCD is quadr...

Question

ABCD is quadrilateral , AC = 19 cm. the length of perpendicular from B and D on AC are 5 cm 7 cm respectively. Then, the area of ABCD in sq. cm is:

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Solution

Area of Quadrilateral=area of $△ A C D +$ area of $(△ A B C)$
$= \frac{1}{2} \times A C \times D E + \frac{1}{2} \times A C \times B F$
$= \frac{1}{2} \times 19 \times (5 + 7) = \frac{19 \times 12}{2}$
$= 114 ㎠$

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ABCD is quadrilateral , AC = 19 cm. the length of perpendicular from B and D on AC are 5 cm 7 cm respectively. Then, the area of ABCD in sq. cm is:

Area of Quadrilateral=area of △ACD+ area of (△ABC)=12×AC×DE+12×AC×BF=12×19×(5+7)=19×122=114㎠

Area of Quadrilateral=area of $△ A C D +$ area of $(△ A B C)$
$= \frac{1}{2} \times A C \times D E + \frac{1}{2} \times A C \times B F$
$= \frac{1}{2} \times 19 \times (5 + 7) = \frac{19 \times 12}{2}$
$= 114 ㎠$