MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vectors and Its Types

ABCDE is a pe...

Question

$A B C D E$ is a pentagon. the resultant of the forces $\to A B + \to B C + \to D C + \to E D + \to A E = k \to A C$ , then find the value of $k$

Open in App

Solution

Given:- $A B C D E$ is apentagon and $\to A B + \to B C + \to D C + \to E D + \to A E = k \to A C$
To find:- $k = ?$
Sol:-
Let $R$ be the resultant force.
Therefore,
$R = \to A B + \to B C + \to A E + \to D C + \to E D + \to A C$
$R = (\to A B + \to B C) + (\to A E + \to E D + \to D C) + \to A C$
$R = \to A C + \to A C + \to A C$
$\Rightarrow R = 3 \to A C$
Now,
$∵ R = \to A B + \to B C + \to D C + \to E D + \to A E + \to A C$
$\Rightarrow R - \to A C = \to A B + \to B C + \to D C + \to E D + \to A E$
$\Rightarrow 3 \to A C - \to A C = k \to A C$
$\Rightarrow k = 2$

Suggest Corrections

thumbs-up

0

Similar questions

A B C D E

is a pentagon, then

\to A B + \to A E + \to B C + \to D C + \to E D + \to A C

A B C D

is a quadrilateral. Forces

\to B A, \to B C, \to C D

\to D A

act at a point. Their resultant is:

Q. If Five forces

\to A B, \to A C, \to A D, \to A E, \to A F

act at the vertex A of a regular hexagon ABCDEF, then their resultant is? (where O is the centroid of the hexagon)

Q. Consider the regular hexagon

A B C D E F

O

\to A B, \to A C, \to A D, \to A E, \to A F

act at the vertex

A

of a regular hexagon

A B C D E F

, then their resultant is

A B C D E F

be a regular hexagon and let

O

be its center. If forces

\to A B

\to A C

\to A D, \to A E, \to A F

act at a point then their resultant is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Vector Intuition

PHYSICS

Watch in App

explore_more_icon

Explore more

Vectors and Its Types

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon