$A B C D E$ is a regular pentagon. A star of five points $A C E B D A$ is formed to join their alternate vertices. The sum of all five vertex angles of this star is

Two right angle

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Three right angle

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Four right angle

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Five right angle

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Solution

The correct option is A Two right angle
$∠ y = ∠ D + ∠ A$
$∠ x = ∠ B + ∠ E$
$∠ c + ∠ x + ∠ y = 180^{\circ}$
$∠ C + ∠ B + ∠ E + ∠ D + ∠ A = 180^{\circ}$

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Similar questions

A B C D E

A C E B D A

5

Find the sum of all the angles at the five vertices of the adjoining star.

∠ x + ∠ y + ∠ z + ∠ t + ∠ u

Assertion: Two diameters of a circle intersect each other at right angles. Then the quadrilateral formed by joining their end-points is a square.

Reason: Angle in a semi-circle is a right angle.

Which of the following options is correct?

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