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Question

ABCDE is a regular pentagon of uniform wire. The rate of heat entering at A and leaving at C is equal. If TB and TD are temperatures of B and D. Find the temperature of C (TC)

A
3TB+2TD5
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B
3TD2TB
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C
3TB2TD
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D
can have any value
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Solution

The correct option is B 3TD2TB

Let
H1 be heat currents in section ABC
H2 be heat currents in section AEDC
R be the thermal resistance of each rod.

Thermal resistance of section ABC is 2R(two rods AB , BC are in series)

Thermal resistance of section AEDC is 3R
(three rods AE,ED,DC are in series)

Then using thermal analogy of Ohms law

TATC=2RH1=3RH2
H1H2=32

also,
TBTC=RH1
TDTC=RH2

TBTCTDTC=RH1RH2=32

TC=3TD2TB

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