ABCDEF are the vertices of a regular hexagon- A-B-a-B-C-b- then the vectors of AE and EF are

The correct option is B 2b⃗ a⃗, b⃗ AE=AB+BC+CD+DE #160; #160; #160; #160; =a⃗+b⃗+b⃗ a⃗ a⃗ #160; #160; #160; #160; =2 ...

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Properties of Parallelogram

ABCDEF are th...

Question

$A B C D E F$ are the vertices of a regular hexagon. $\to A B = \to a, \to B C = \to b$ , then the vectors of $¯ ¯¯¯¯¯¯ ¯ A E$ and $¯ ¯¯¯¯¯¯ ¯ E F$ are

\to a - \to b, \to a

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\to b - \to a, \to a

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2 \to b - \to a, - \to b

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\to a - \to b, \to b

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Solution

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Similar questions

\to A B = \to a, \to B C = \to b

\to A B = \to a, + \to b

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\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

| \to a + \to b | = | \to a - \to b |

(\to a, \to b) = \frac{π}{2}

\to a, \to b, \to a + \to b

(\to a, \to b) = \frac{2 π}{3}

| \to b | \to a + | \to a | \to b

| \to b | \to a - | \to a | \to b

\to a

\to b

(\to a - \to b) \times [(\to b + \to a) \times (2 \to a + \to b)] = \to a + \to b

θ

\to a

\to b

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