ABCDEF is a hexagon- Prove that A-E- A-B- A-C- A-F-

[ From vector properties:; AB = ED #160;; AE + AB = AD #160;; Simil ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Addition

ABCDEF is a h...

Question

$A B C D E F$ is a hexagon. Prove that $\to A E +$ $\to A B =$ $\to A C$ + $\to A F$ .

Open in App

Solution

Suggest Corrections

Similar questions

A B C D E F

\to A B - -- - + \to A C - -- - + \to A E - -- - + \to A F - -- - = 2 \to A D - -- - .

A B C D E F

\to A B + \to A C + \to A D + \to A E + \to A F = λ \to A D

λ =

A B C D E F

\to A B + \to A C + \to A D + \to A E + \to A F = k \to A D

k

A B C D E F

O

\to A B, \to A C, \to A D, \to A E, \to A F

A

A B C D E F

A B C D E F

O

\to A B

\to A C

\to A D, \to A E, \to A F

Join BYJU'S Learning Program