ABD and ACE are the two tangents to the circle having centre O, then AB + AC equals ______ of triangle AMN.
A
2s
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B
s/2
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C
3s
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D
s
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Solution
The correct option is A 2s Let P be the point of contact of tangent MN to the circle.
AB = AC [ Tangents drawn from the same external point are always equal to each other]
Similarly,
MP= MB and NP = NC
So,
AB + AC = AM + MB +AN+ NC
= AM+ MP + AN + NP
[ MP= MB and NP = NC]
= AM + AN + (MP + NP)
= AM + AN + MN
=2s
Hence, a is the correct option.