ABDE is a trapezium with AE∥BD and ED⊥BD, and AC is drawn parallel to the side DE.
Find the values of cot θ and cosec θ respectively, from the figure.
43,53
Consider the figure ACDE
AE∥CD and AC∥DE and AC⊥CD
∴ ACDE is a rectangle.
CD = AE = 10 units
BC = BD - CD = 16 - 10 = 6
Now, in △ABC,
∠C=90∘
Now, from Pythagoras theorem,
AC2+BC2=AB2
AC2+62=102
AC=√100−36=8
cot θ=ACBC=86=43cosec θ=ABBC=106=53