Let, the speed of train
=x km/h and the speed of the taxi
=y km/h.
Now using time=distancespeed, we get,
300x+200y=112 ...........(1) and
260x+240y=5+3660=5+35=285 ..........(2)
Let, 1x =m and 1y =n then,
600m+400n=11 ..........(3)
1300m+1200n=28 .........(4)
Now, equation (3)×3− equation (4)×4 we get,
500m=5⇒m=1100
⇒x=100 km/h.
Putting the value of m in equation (3) we get,
n=5400=180
⇒y=80 km/h.
Speed of train =100 km/h.
Speed of taxi =80 km/h.