Question

Abraham, on his deathbed, prepared his will in which he divided his property equally among his widow and their three sons: Brandon, Coleman and Davis. Some years later, Brandon died leaving 60% of his property to his widow and the rest to his brothers Coleman and Davis together, who shared it amongst them equally. When Coleman made his will, he kept half of his property for his widow and the rest he bequeathed to his younger brother Davis. When Davis died some years later, he shared his property equally among his widow, his daughter and his mother. The mother now owns Rs. 2500000 worth of property. What is the worth of the entire property?

• A. 5000000
• B. 6250000
• C. 7500000
• D. 3750000

Answer 1

The correct option is B 6250000

Let the total property of the Abraham be =Rs.x
After Alphonso’s death, money possessed by the family members would be
Wife=$\frac{x}{4}$,Brandon$=\frac{x}{4}$,
Coleman$=\frac{x}{4}$,Davis$=\frac{x}{4}$
After Brandon’s death, money possessed by each of them would be -
Abraham’s wife$=\frac{x}{4}$, Brandon = 0,Brandon’s wife$=\frac{x}{4}\times \frac{3}{5}=\frac{3x}{20}$ Coleman$=\frac{x}{4}+(\frac{x}{4}\times \frac{1}{5})=\frac{3x}{10}$, Dave$=\frac{x}{4}+(\frac{x}{4}\times \frac{1}{5})=\frac{3x}{10}$
After Coleman’s death, money possessed by them
Abraham’s wife$=\frac{x}{4}$, Brandon=0,Brandon’s wife has $\frac{3x}{20},$Coleman has 0,
Coleman’s wife$=\frac{3x}{20},$ Davis$=\left(\frac{3x}{10}\right)+\left(\frac{3x}{20}\right)=\frac{9x}{20}$
After Davis’s death, money possessed by them is:
Abraham’s wife$=\left(\frac{x}{4}\right)+\left(\frac{3x}{20}\right)=\frac{2x}{5},$ Brandon has 0,Brandon’s wife has $\frac{3x}{20},$ Coleman has 0,
Coleman’s wife has $\frac{3x}{20,}$Davis’s wife has $\frac{3x}{20},$ Davis’s daughter has $\frac{3x}{20}.$
Now,given that $\frac{2x}{5}=2500000\Rightarrow x=6250000$