Acceleration a of a body of radius R rolling down an inclined plane of inclination - is given byA- a-g sin- -1-K - R-B- a - g sin- -1- R 2 - K 2-C- a - g sin- -1- R - K -D- a - g sin- -1- k 2 - R 2-

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Standard IX

Physics

Speed / Velocity Time Graphs

Acceleration ...

Question

Acceleration (a) of a body of radius R rolling down an inclined plane of inclination θ is given by

a = g sinθ / [1 + (k²/R²)]

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a = g sinθ / [1 + (R/K)]

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a = g sinθ / [1 + (K/R)]

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a = g sinθ / [1 + (R²/ K²)]

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Solution

The correct option is A
a = g sinθ / [1 + (k²/R²)]

Acceleration (a) of a body of radius R rolling down an inclined plane of inclination θ is given by a = g sinθ / [1 + (K²/ R²)]

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Acceleration (a) of a body of radius R rolling down an inclined plane of inclination θ is given by

The correct option is A a = g sinθ / [1 + (k2/R2)] Acceleration (a) of a body of radius R rolling down an inclined plane of inclination θ is given by a = g sinθ / [1 + (K2/ R2)]

The correct option is A
a = g sinθ / [1 + (k²/R²)]

Acceleration (a) of a body of radius R rolling down an inclined plane of inclination θ is given by a = g sinθ / [1 + (K²/ R²)]