Question

Acceleration displacement graph of a particle executing S.H.M is as shown in given figure The time period of its oscillation is (in sec_)

• A. $\pi /2$
• B. $2\pi$
• C. $\pi$
• D. $\pi /4$

Answer 1

Answer: (B)

$2\pi$

In simple harmonic motion,

$a=-{\omega }^{2}x$

$a=-\frac{k}{m}x$. . . . . . . . .(1)

From the graph, slope$=-1$

$-\frac{k}{m}=-1$

$\frac{k}{m}=1$

$\frac{m}{k}=1$

Time period, $T=2\pi \sqrt{\frac{m}{k}}$

$T=2\pi \sqrt{1}$

$T=2\pi$

The correct option is B.