Question

Acceleration due to gravity 'g' in terms of mean density of the Earth, 'd ' (where R is radius of the Earth and G is universal gravitational constant) is

• A. 4πr²dG
• B. 4πr²/G
• C. 3/4πRdG
• D. 4/3πRdG

Answer 1

The correct option is D

4/3πRdG

g = $\frac{GM}{R^2}$

where, M= volume x density, and volume = $\frac{4}{3}$$\pi$ $R^3$

By substituting these in the expression, we obtain ‘g’ in terms of ‘d’ and G

g = $\frac{4}{3}$$\pi$RdG