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Question

Acceleration due to gravity on earth is g . Find the effective value of acceleration due to gravity at height 32km from sea level 
R= 6400 km


Solution

Variation of acceleration due to gravity with height is given by the relation :
g ' = g R^2/( R + h)^2     ........(1)
where g is the value of acceleration due to gravity on the earth's surface = 9.8 m/s2
R is the radius of the earth = 6400 km
h is the height above the surface of the earth  = 32 km
g'=9.8(6400)^2/(6400+32)^2
g'=401408000/41370624
g'=9.702m/s^2

Physics

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