Question

# Acceleration due to gravity on earth is g . Find the effective value of acceleration due to gravity at height 32km from sea level  Re = 6400 km

Solution

## Variation of acceleration due to gravity with height is given by the relation : g ' = g R^2/( R + h)^2     ........(1) where g is the value of acceleration due to gravity on the earth's surface = 9.8 m/s2 R is the radius of the earth = 6400 km h is the height above the surface of the earth  = 32 km g'=9.8(6400)^2/(6400+32)^2 g'=401408000/41370624 g'=9.702m/s^2Physics

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