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Variation of G Due to Height and Depth

Acceleration ...

Question

Acceleration due to gravity on the surface of Earth is maximum at the

A

Poles

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B

Equator

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C

Tropic of cancer

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D

Tropic of capricorn

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Solution

The correct option is B Poles
Poles
Acceleration due to gravity is maximum at poles and minimum at equator as earth is not perfectly round and slightly flat at the poles. Thus, $R$ for poles is least and $g = \frac{G M}{R^{2}}$

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