Acceleration of a body is given by a=(4-3v) m/s^{2^{}}. Speed v is in m/s and t is in second. If initial velocity is zero then terminal velocity of body is

Open in App

Solution

Suggest Corrections

184

Similar questions

Q. The motion of a body is given by the equation

\frac{d v}{d t} = 6 - 3 v

, where

v

is speed in

m / s

and

t

is time in seconds. If the body is at rest at

t = 0

, then

The motion of a body is given by $\frac{d v}{d t} = 6 - 3 v$ where $v$ is the velocity (in $m s^{- 1}$ ) at a time $t$ (in seconds). The body is at rest at t = 0. The terminal speed of the body is

Q. The velocity acquired by a body moving with uniform acceleration is

30 m / s

2

seconds and

60 m / s

4

seconds. The initial velocity is:

Q. If the distance travelled by a body in the nth second is given by (4+6n) m then find the initial velocity and acceleration of the body.

Q. If the distance travelled by a body in the

n^{t h}

second is given by (4 + 6 n) m, then find the initial velocity and acceleration of the body respectively.

Join BYJU'S Learning Program