Acceleration of a charged particle of charge ' $q$ ' and mass ' $m$ ' moving in a uniform electric field of strength ' $E$ ' is :

\frac{q E}{m}

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\frac{m}{q E}

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m q E

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\frac{q}{m E}

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Solution

The correct option is D $\frac{q E}{m}$
The particle accelerates because of the electrostatic force acting on the particle.
Electrostatic force $F_{e} = q E$
$∴$ Acceleration of particle $a = \frac{F_{e}}{m} = \frac{q E}{m}$

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Acceleration of a charged particle of charge 'q' and mass 'm' moving in a uniform electric field of strength 'E' is :

The correct option is D qEmThe particle accelerates because of the electrostatic force acting on the particle.Electrostatic force Fe=qE∴ Acceleration of particle a=Fem=qEm

Acceleration of a charged particle of charge ' $q$ ' and mass ' $m$ ' moving in a uniform electric field of strength ' $E$ ' is :

The correct option is D $\frac{q E}{m}$
The particle accelerates because of the electrostatic force acting on the particle.
Electrostatic force $F_{e} = q E$
$∴$ Acceleration of particle $a = \frac{F_{e}}{m} = \frac{q E}{m}$