Acceleration of particle moving in straight line can be written as a-dv-dt-vdv-dx- From the given graph find acceleration at x-20 m-

The correct option is A 100 m/s^2 From graph dvdx=90 5040 20=4020dvdx=2 v (at x=20)=50 m/s a=vdvdx⇒ a=50×2=100 m/s^2 ...

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Standard XII

Physics

Instantaneous Velocity

Acceleration ...

Question

Acceleration of particle moving in straight line can be written as $a = \frac{d v}{d t} = v \frac{d v}{d x}$ . From the given graph find acceleration at $x = 20 m$ .

100 m / s^{2}

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50 m / s^{2}

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25 m / s^{2}

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200 m / s^{2}

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Solution

The correct option is A $100 m / s^{2}$
From graph $\frac{d v}{d x} = \frac{90 - 50}{40 - 20} = \frac{40}{20} \frac{d v}{d x} = 2$

$v (a t x = 20) = 50 m / s$
$a = v \frac{d v}{d x} \Rightarrow a = 50 \times 2 = 100 m / s^{2}$

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Acceleration of particle moving in straight line can be written as a=dvdt=vdvdx. From the given graph find acceleration at x=20m.

The correct option is A 100m/s2From graph dvdx=90−5040−20=4020dvdx=2v(atx=20)=50m/sa=vdvdx⇒a=50×2=100m/s2

Acceleration of particle moving in straight line can be written as $a = \frac{d v}{d t} = v \frac{d v}{d x}$ . From the given graph find acceleration at $x = 20 m$ .

The correct option is A $100 m / s^{2}$
From graph $\frac{d v}{d x} = \frac{90 - 50}{40 - 20} = \frac{40}{20} \frac{d v}{d x} = 2$

$v (a t x = 20) = 50 m / s$
$a = v \frac{d v}{d x} \Rightarrow a = 50 \times 2 = 100 m / s^{2}$