wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

Acceleration of the particle in a rectilinear motion is given as a=2t6 in (m/s2). The displacement as a function of time t respectively is
(Given, at t=0,u=2 m/s,x=2 m)

A
2t333t2+2t+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t333t2+2t
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
t333t2+2t+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
t333t2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B t333t2+2t
Given, a(t)=2t6
As we know that the velocity as a fuction of time is given by
vudv=t0(2t6)dt
[v]vu=[t26t]t0
vu=t26t
v2=t26t v(t)=t26t+2
Now, displacement is given by
x(t)=t0v(t)dt=t0(t26t+2)dt
x(t)=[t333t2+2t]t0
x(t)=(t333t2+2t)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon