Acceleration of the particle in a rectilinear motion is given as a=3t2−2t+5 in (m/s2). The velocity of the particle as a function of time t is
(Given, at t=0,u=−4m/s)
A
t3−t2+5t+4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t3−t2+5t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t3−t2+5t−4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
t3+t2+5t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ct3−t2+5t−4 Given, a(t)=3t2−2t+5
As we know that the velocity as a fuction of time is given by ∫vudv=∫t0(3t2−2t+5)dt ⇒[v]vu=[t3−t2+5t]t0 ⇒v−u=t3−t2+5t
Or, ⇒v+4=t3−t2+5t⇒v(t)=t3−t2+5t−4