Acceleration of the particle when its velocity becomes half of the initial velocity.

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Solution

$V = - (\frac{20}{50}) x$
$V = \frac{- 2 x}{5}$
$a = \frac{d v}{d t} = \frac{- 2}{5} \frac{d x}{d t} = \frac{- 2 V}{5}$
$a = \frac{- 2 V}{5}$
initial velocity $(u) = 20 m / s$
$\frac{u}{2} = 10 m / s$
$a = \frac{- 2}{5} (10) = - 4 m / s^{2}$ .

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Acceleration of the particle when its velocity becomes half of the initial velocity.

V=−(2050)xV=−2x5a=dvdt=−25dxdt=−2V5a=−2V5initial velocity (u)=20m/su2=10m/sa=−25(10)=−4m/s2.

$V = - (\frac{20}{50}) x$
$V = \frac{- 2 x}{5}$
$a = \frac{d v}{d t} = \frac{- 2}{5} \frac{d x}{d t} = \frac{- 2 V}{5}$
$a = \frac{- 2 V}{5}$
initial velocity $(u) = 20 m / s$
$\frac{u}{2} = 10 m / s$
$a = \frac{- 2}{5} (10) = - 4 m / s^{2}$ .