According to Archimedes principle, relative density is:

\frac{w e i g h t o f s u b s t a n c e i n a i r}{w e i g h t o f s u b s t a n c e i n w a t e r}

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\frac{w e i g h t o f s u b s t a n c e i n w a t e r}{w e i g h t o f s u b s t a n c e i n a i r}

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\frac{w e i g h t o f s u b s t a n c e i n a i r}{l o s s o f w e i g h t i n w a t e r}

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\frac{l o s s o f w e i g h t i n w a t e r}{w e i g h t o f s u b s t a n c e i n a i r}

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Solution

The correct option is A $\frac{w e i g h t o f s u b s t a n c e i n a i r}{l o s s o f w e i g h t i n w a t e r}$
R.D. = mass of substance/ mass of equal volume of water
Since weight is proportional to mass, we have
R.D. = weight of substance/ weight of equal volume of water
When a body is immersed in water, it displaces its own volume of water. According to Archimedes principle, upthrust on the body is equal to the weight of this displaced volume of water, which is also equal to loss of weight of the body. Hence 'weight of equal volume of water' can be replaced by upthrust or loss of weight in water.
R.D. = weight of substance in air / loss of weight in water

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