Question

According to Bohr's atomic model, angular momentum of electron in nth orbit is equal to an integral multiple of

• A. $2h/\pi$
• B. $h/2\pi$
• C. $h\pi /2$
• D. $h/\pi$

Answer 1

The correct option is B $h/2\pi$

$\text{Angular momentum of an electron in the}$

$n^{\text{th}}\text{orbit is}$

$p=\frac{nh}{2\pi }$

$h\to \text{planck's constant}$

$p=n\times \frac{h}{2\pi }$

$n\to \text{ineger}$

$\therefore P\text{is integral multiple of}\frac{h}{2\pi }$