Question

According to Bohr's model, if the kinetic energy of an electron in $2^{nd}$ orbit of $H{e}^{+}$ is $x$, then what should be the ionisaion energy of the electron revolving in $3^{rd}$ orbit of $m^{5+}ions>$

• A. $X$
• B. $4X$
• C. $x/4$
• D. $2X$

Answer 1

The correct option is B $4X$

$\begin{array}{c}X=13\cdot 6\frac{{\left(2\right)}^2}{{\left(2\right)}^2}\\ =13\cdot 6\\ X^{\prime }=13\cdot \frac{{\left(6\right)}^2}{{\left(3\right)}^2}\\ =13\cdot 6\times \frac{36}{9}\\ =4X\\ Hence,optionBiscorrectanswer.\end{array}$