Question

According to Bohr's theory angular momentum of an electron in 6th orbit is

• A. $2.5\frac{h}{\pi }$
• B. $6\frac{h}{\pi }$
• C. $3\frac{h}{\pi }$
• D. $\frac{2.5h}{\pi }$

Answer 1

The correct option is C $3\frac{h}{\pi }$

in $n^{th}$ orbit the angular momentum $mvr=\frac{nh}{2\pi }$

put $n=6$ we get angular momentum = $\frac{3h}{\pi }$

option C as the answer.