According to Bohr theory, the angular momentum for an electron of $5$ th orbit is:

5 h / π

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2.5 h / π

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5 π / h

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25 h / π

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Solution

The correct option is B $2.5 h / π$
$E x p l a n a t i o n :$

According to $B o h r^{'} s T h e o r y$ , the angular momentum of the electron in nth:

$m v r = \frac{n h}{2 Π} \to (1)$

$∴$ the angular moment of the 5th orbit will be:

here put $n = 5$ in equation 1

Then we get,

$m v r = \frac{5 h}{2 Π} = \frac{2.5 h}{Π}$

$∴ T h e a n g u l a r m o m e n t u m o f t h e 5 t h o r b i t i s \frac{2.5 h}{Π}$

$H e n c e t h e c o r r e c t a n s w e r i s o p t i o n (B) .$

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