Question

According to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order:

• A. $C{H}_{3}CO{O}^{-}>C{l}^{-}>O{H}^{-}$
• B. $C{H}_{3}CO{O}^{-}>O{H}^{-}>C{l}^{-}$
• C. $O{H}^{-}>C{H}_{3}CO{O}^{-}>C{l}^{-}$
• D. $O{H}^{-}>C{l}^{-}>C{H}_{3}CO{O}^{-}$

Answer 1

The correct option is C $O{H}^{-}>C{H}_{3}CO{O}^{-}>C{l}^{-}$

Relative strength of bases can be shown by their conjugated acids.
A strong conjugate acid will have a weak base while a weak conjugate acid will have a strong base.

Conjugate acid of $O{H}^{-}$ is $H_{2}O$ .Conjugate acid of
$C{H}_{3}CO{O}^{-}$ is $C{H}_{3}COOH$ which is a stronger acid than $H_{2}O.$
While conjugate acid of $C{l}^{-}$ is HCl which is the strongest acid as compared with $H_{2}OandC{H}_{3}COOH$.
So the order of relative strength of bases is:
$O{H}^{-}>C{H}_{3}CO{O}^{-}>C{l}^{-}$