Question

According to $C.E$ van der Waal, the interatomic potential varies with the average interatomic distance $\left(R\right)$ as

• A. $R^{-1}$
• B. $R^{-2}$
• C. $R^{-4}$
• D. $R^{-6}$

Answer 1

The correct option is D $R^{-6}$

According to the relation

$V\left(r\right)=\frac{-3}{4}\frac{{{\alpha }^2}_{0}l}{{\left(4\pi {\epsilon }_0\right)}^2{R}^6}$

$V\left(r\right)\propto \frac{1}{R^6}$

$V\left(r\right)\propto R^{-6}$