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Question

According to cahn-Ingold-prelog sequence rules, the correct order of priority of the given groups is


A

-COOH > - CH2OH > -OH > -CHO

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B

-COOH > -CHO > - CH2OH > -OH

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C

-OH > - CH2OH > -CHO > -COOH

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D

-OH > -COOH >-CHO > - CH2OH

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Solution

The correct option is D

-OH > -COOH >-CHO > - CH2OH


When the atom (which is directly attached to the asymmetric carbon atom) of a group has higher
atomic number, the group gets higher priority. Groups with atoms of comparable atomic number
having double or triple bond, have high priority than those have single bond.

OH>COOH>CHO>CH2OH


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