According to Charle's law :

{(\frac{d V}{d T})}_{P} = k (c o n s t a n t)

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{(\frac{d V}{d T})}_{P} = P

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{(\frac{d V}{d T})}_{P} = V

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{(\frac{d V}{d T})}_{P} = T

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Solution

The correct option is A ${(\frac{d V}{d T})}_{P} = k (c o n s t a n t)$
According to Charle's law ${(\frac{d V}{d T})}_{P} = k (c o n s t a n t)$ It states that at constant pressure, the volume of a given mass of a gas is directly proportional to abosolute temperature.
$V \propto T$
$\frac{V}{T} =$ constant (mass and P constant)

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Similar questions

(d V / d T)_{p} = - K

(d V / d T)_{p} = K

Boyle's law may be represented as

1.[dp/dv]T=K/V

2.[dp/dv]T=-K/V

3.[dp/dv]T=-K/V

4.[dp/dv]T=K/V^2

{(\frac{d E_{c e l l}}{d T})}_{p} > 0

△ S

△ S = n F T {(\frac{d E}{d T})}_{p}

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