According to Charles law:

(d V / d T)_{P} = K

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(d V / d T)_{P} = - K

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(d V / d T)_{P} = - K / T

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none of these

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Solution

The correct option is A $(d V / d T)_{P} = K$
According to Charle's law, the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature.

$V α T$

$V = K T$

$(\frac{d V}{d T})_{p} = K$

Hence, option (A) is correct.

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Similar questions

(d V / d T)_{p} = - K

(d V / d T)_{p} = K

Boyle's law may be represented as

1.[dp/dv]T=K/V

2.[dp/dv]T=-K/V

3.[dp/dv]T=-K/V

4.[dp/dv]T=K/V^2

{(\frac{d E_{c e l l}}{d T})}_{p} > 0

△ S

△ S = n F T {(\frac{d E}{d T})}_{p}

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