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Question

According to Charles law V= KT where k is constant .The unit of K is :

m^{3} K^{- 1}

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m^{- 3} K^{1}

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^{3}

^{2}

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^{- 3}

^{- 2}

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Solution

The correct option is B $m^{3} K^{- 1}$
According to charles law, $V = k T$
$k = \frac{V}{T} = \frac{m^{3}}{K} = m^{3} K^{- 1}$
where $m =$ meter and $K =$ kelvin

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