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Strength of Electrostatic Force

According to ...

Question

According to Coulomb's Law, which is the correct relation for the following diagram?

A

q_{1} q_{2} < 0

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B

q_{1} q_{2} > 0

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C

q_{1} q_{2} = 0

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D

q_{1} q_{2} >> 100 C

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Solution

The correct option is A $q_{1} q_{2} < 0$
According to Coulomb's law, ${\to F}_{12} = - {\to F}_{21}$

There is a force of attraction and the charge must be unlike charge.

and we know that $F = \frac{q_{1} q_{2}}{4 π ε_{0} r^{2}}$

For attractive force, $q_{1} q_{2} < 0$

$q_{1} = +$

$q_{2} = -$

$q_{1} q_{2} < 0$

The correct option is A.

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