According to $E A N$ rule, how many $C O$ groups should be attached to $F e$ ?

4

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5

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6

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8

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Solution

The correct option is B $5$
According to Sidgwick,
The sum of electron on the central metal atomor ion and electrons donated from the ligands is called effective atomic number(EAN).
$E A N$ = atomic number of nearest noble gas.
$E A N = Z - O . S + 2 \times C . N$
Z=atomic number of central metal atom
O.S=Oxidation state of central metal atom
C.N=coordination number of ligands.
Fe has atomic number 26.
Nearest noble gas is 36
Let co-ordination is 6
$36 = 26 - 0 + \times x$
$x = 5$
so $5 C O$ groups should be attached.

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Assertion (A) : According to EAN rule, ferricyanide is not a stable complex compound.

Reason (R) : EAN of Fe in ferricyanide is 35.

18

[C u (N H_{3})_{4}]^{2 +}, [C u (e n)_{3}]^{2 +}, [C u (C N)_{4}]^{3 -}

[F e (C N)_{6}]^{4 -}, [F e (C N)_{6}]^{3 -}, F e (C O)_{6}

[N i (N H_{3})_{6}]^{2 +}, [N i (C N)_{4}]^{2 -}, [N i (C O)_{4}]

[C r (N H_{3})_{6}]^{3 +}, [C r (C O)_{6}]

[C o (N H_{3})_{6}]^{3 +}, [C o C l_{4}]^{2 -}

(F e_{3} O_{4})

F e_{3} O_{4} + 4 C O \to 3 F e + 4 C O_{2}

F e_{3} O_{4}

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