Question

According to figure, if $\angle BAC={80}^{\circ }$, then find the value of $\angle BCP$.

Answer 1

R.E.F image

Acc. to figure of $\angle BAC={80}^{\circ }$

then find the volume of $\angle BCP$

Sol Given $\angle BAC={80}^{\circ }$

from fig.$\angle BOC={90}^{\circ }$

[Angle at center to the chord]

$\therefore OB=OC$ [radii]

$\therefore \angle OCB={45}^{\circ }$

$\therefore \angle OCP=\angle OCB+\angle BCP$

$\therefore {90}^{\circ }={45}^{\circ }+\angle BCP$

$\therefore \angle BCP={45}^{\circ }$