According to Freundlich isotherm, the above graph will be true when:

P = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{n} = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{n} = \infty

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{n} = 0$
Generally according to Freundlich adsorption theory, at high pressure $\frac{1}{n}$ value tends to 0 and hence the amount of substance adsorbed becomes independent of pressure.

So, above graph is valid if $\frac{1}{n} = 0$ and high pressure.

So the answer is option C.

Suggest Corrections

Similar questions

According to Freundlich isotherm, the above graph will be true when:

Q. In the mathematical relation of Freundlich adsorption isotherm, the value of

\frac{1}{n}

0 \leq \frac{1}{n} \leq 1

Q. In the Freundlich adsorption isotherm, log

(\frac{x}{m}) = l o g k + \frac{1}{n} l o g p,

the value of n is

A train consists of n carriages and there are P passengers. Each one of the P passengers randomly selects the carriage in which he will ride. On the basis of above information, answer

$^{n} C_{1} 1^{p} -^{n} C_{2} 2^{p} +^{n} C_{3} 3^{p} . . . . + (- 1)^{n - 1 n} C_{n} n^{p}$ is equal to,

Q. The equation for Freundlich adsorption isotherm is

a)

\frac{x}{m} = k p^{\frac{1}{n}}

(l n x) = l n (m k) + \frac{1}{n} l n p

\frac{x}{m} = k p^{- n}

d) Only a and b

Join BYJU'S Learning Program

According to Freundlich isotherm, the above graph will be true when:

The correct option is C 1n=0Generally according to Freundlich adsorption theory, at high pressure 1n value tends to 0 and hence the amount of substance adsorbed becomes independent of pressure.So, above graph is valid if 1n=0 and high pressure. So the answer is option C.