Question

According to Heisenberg's uncertainty principle:

• A. $E=h\nu$
• B. $\lambda =\frac{h}{p}$
• C. $\Delta x.\Delta p\ge \frac{h}{2\pi }$
• D. $\Delta x.\Delta p\ge \frac{h}{4\pi }$

Answer 1

The correct option is D $\Delta x.\Delta p\ge \frac{h}{4\pi }$

Heisenberg’s uncertainty principle states that it is impossible to measure or calculate exactly, both the position and the momentum of an object simultaneously.
$\Delta x.\Delta p\ge \frac{h}{4\pi }$
Where $\Delta x$ is uncertainty in position and $\Delta p$ is uncertainty in momentum.