According to Keplers law of planetry motion, if $T$ represents time period and r is orbital radius, then for two planets these are related us :

{\frac{T_{1}}{T_{2}}}^{3 / 2} = \frac{r_{1}}{r_{2}}

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\frac{T_{1}}{T_{2}} = [\frac{r_{1}}{r_{2}}]

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{[\frac{T_{1}}{T_{2}}]}^{2} = {[\frac{r_{1}}{r_{2}}]}^{3}

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\frac{T_{1}^{2}}{T_{2}} = \frac{r_{1}^{3}}{r_{1}}

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Solution

The correct option is B ${[\frac{T_{1}}{T_{2}}]}^{2} = {[\frac{r_{1}}{r_{2}}]}^{3}$
By Kepler's third law of planetry motion,
$T^{2} \infty R^{3}$
$[\frac{T_{1}}{T_{2}}]^{2} = [\frac{r_{1}}{r_{2}}]^{3}$

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According to Keplers law of planetry motion, if T represents time period and r is orbital radius, then for two planets these are related us :

The correct option is B [T1T2]2=[r1r2]3By Kepler's third law of planetry motion,T2∞R3[T1T2]2=[r1r2]3

According to Keplers law of planetry motion, if $T$ represents time period and r is orbital radius, then for two planets these are related us :

The correct option is B ${[\frac{T_{1}}{T_{2}}]}^{2} = {[\frac{r_{1}}{r_{2}}]}^{3}$
By Kepler's third law of planetry motion,
$T^{2} \infty R^{3}$
$[\frac{T_{1}}{T_{2}}]^{2} = [\frac{r_{1}}{r_{2}}]^{3}$