Question

According to Kohlrausch law, the limiting value of molar conductivity of an electrolyte $A_{2}B$:

• A. ${\lambda }_{A^{+}}+{\lambda }_{B^{2-}}$
• B. $\frac{1}{2}$${\lambda }_{A+}+{\lambda }_{B^{2-}}$
• C. $2{\lambda }_{A^{+}}$ +$\frac{1}{2}{\lambda }_{B^{2-}}$
• D. $2{\lambda }_{A^{+}}+{\lambda }_{B^{2-}}$

Answer 1

The correct option is D $2{\lambda }_{A^{+}}+{\lambda }_{B^{2-}}$

$A_{2}B\rightleftharpoons 2A^{+}+B^{2-}$

According to Kohlrausch law

${\lambda }_m^{\infty }=2{\lambda }_{A^{+}}+{\lambda }_{B^{2-}}$ at $\infty$ dilution.

So, option D is correct.