According to Maxwell-Boltzman distribution law of molecular velocities of gases, the average translational kinetic energy is:

\frac{K T}{2}

per molecule

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K T

per molecule

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R T

per molecule

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\frac{3}{2} K T

per molecule

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Solution

The correct option is B $\frac{3}{2} K T$ per molecule
For a given temperature, all gas molecules, no matter what their mass, have the same average translational kinetic energy namely $\frac{3}{2} k T$ per molecule.

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